How about ANY FINITE SEQUENCE AT ALL?

  • BrainInABox
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    1 day ago

    Are you trying to say the answer to their question is no? Because if so, you’re wrong, and if not I’m not sure what you’re trying to say.

    • ped_xing [he/him]@hexbear.net
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      1 day ago

      The conclusion does not follow from the premises, as evidenced by my counterexample. It could be the case that every finite string of digits appears in the decimal expansion of pi, but if that’s the case, a proof would have to involve more properties than an infinite non-repeating decimal expansion. I would like to see your proof that every finite string of digits appears in the decimal expansion of pi.

      • BrainInABox
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        1 day ago

        Well that’s just being pointlessly pedantic, obviously they fucking know that a repeating number of all zeros and ones doesn’t have a two in it. This is pure reddit pedantry you’re doing

        • spireghost@lemmy.zip
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          2 hours ago

          It kind of does come across as pedantic – the real question is just that “Does pi contain all sequences”

          But because of the way that it is phrased, in mathematics you do a lot of problems/phrasing proofs where you would be expected to follow along exactly in this pedantic manner