• liwott@nerdica.net
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    2 years ago

    Can see how this gives a proof of the root formula that is less cryptic for students.

    Now I was wondering naively whether this trick could be used to quickly find one root of higher degrees polynomials.
    Like x3 +b x2 + c x +d, where the sum of the roots is -b and their product is -d.
    So I write x1 = -b/3 + u1, x2 = -b/3 + u2, x3 = -b/3 - u1 -u2.
    But solving for u2(u1) starting for the product is quite barbaric.
    Maybe there’s a better organisation of the u variables?