Day 7: Camel Cards

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  • morrowind
    2·
    1 year ago

    Crystal

    got stuck on both parts due to silly mistakes.
    On the other hand I’m no longer behind!

    code 
    input = File.read("input.txt").lines
rank = {
	'J' => 1,
	'2' => 2,
	'3' => 3,
	'4' => 4,
	'5' => 5,
	'6' => 6,
	'7' => 7,
	'8' => 8,	
	'9' => 9,
	'T' => 10,
	# 'J' => 11,
	'Q' => 12,
	'K' => 13,
	'A' => 14
}

hand = input.map do |line|
	split = line.split
	weights = split[0].chars.map {|c| rank[c]}
	{weights, split[1].to_i}
end

hand.sort! do |a, b|
	a_rank = get_rank(a[0], true)
	b_rank = get_rank(b[0], true)
	
	# puts "#{a}-#{a_rank} #{b}-#{b_rank}"
	next  1 if a_rank > b_rank
	next -1 if b_rank > a_rank

	val = 0
	5.times do |i| 
		val =  1 if a[0][i] > b[0][i]
		val = -1 if b[0][i] > a[0][i]
		break unless val == 0
	end
	val
end

sum = 0
hand.each_with_index do |card, i|
	sum += card[1]*(i+1)
end
puts sum


def get_rank(card : Array(Int32), joker = false ) : Float64 | Int32
	aa = card.uniq

	if joker
		card = aa.map { |c|
			combo = card.map {|a| a == 1 ? c : a }
			{combo, get_rank(combo)}
		}.max_by {|a| a[1]}[0]
		aa = card.uniq
	end
	
	rank = 6 - aa.size
	case rank
	when 3
		return 3.5 if card.count(aa[0]) == 3
		return 3   if card.count(aa[0]) == 2
		return 3   if card.count(aa[1]) == 2
		return 3.5
	when 4
		return 4 if card.count(aa[0]) == 3 || card.count(aa[0]) == 2
		return 4.5
	else 
		return rank
	end
end