As the title says, I just started with linux mint and am falling in love with bash scripts 😍 Actually I’m not sure if it’s considered a script, but I want to delete the last 2 files in all subfolders in a folder. So far I’ve (after great effort) got the terminal to list the files, but I want to delete them. Here is how I get them listed:
for f in *; do ls $f | tail -n 2; done
All their names come satisfyingly up in the terminal. Now what? I tried adding | xargs rm but that didn’t delete them. I also tried something with find command but that didn’t work either. Some folders have 3 items, so I want to delete #2 and 3. Some folders have 15 items so I want to delete #14 and 15. Folders are arranged by name, so it’s always the last 2 that I want to delete.
It’s frustrating to be sooooo clooooose, but also very fun. Any help is appreciated!
When you run the command without the
xargs
bit, like this:for f in \*; do ls $f | tail -n 2; done\
,Does the output give you the full file path, or just the file names?
The full file path will look something like:
/dir1/dir2/actual-file
And of course the file name would just be:
some-file
If you’re getting just the file name, that’s the problem. Unless you’re in the directory with the file you wish to delete,
rm
needs the full path.Edit: grammar
Yea that must be it! It’s spitting out just the file name and not the whole path. There is only 1 level of depth, so I want to remove
so how do I get the whole path into xargs? I tried
xargs "$f"/
but fortunately that didn’t work because it was trying to delete all the directories lmao XDHere’s the command to delete the files:
for f in *; do find ./"$f" -type f | sort | tail -n 2 | xargs -n 1 rm; done
If you want to insure it will target the correct files, first run this command (I HIGHLY recommend you do this first. Verify BEFORE you delete so you don’t lose data):
for f in *; do find ./"$f" -type f | sort | tail -n 2; done
I’ll be adding another comment reply with a breakdown of the command shortly (just need to write it up)
Here’s what’s happening in the command;
for f in *; do
You already know this for loop, which is using the
*
glob to iterate over each directory in the current directory.find ./"$f" -type f
Instead of your original
ls
command, which gives the file names, and not their full paths, we’re using GNUfind
, which outputs the full path of what it finds. The arguments are:./"$f"
- This tellsfind
where to start its search. I double qouted the$f
variable to properly expand the directory name even if it has nonstandard characters in it like spaces.-type f
- This tellsfind
what kind of file object to look for. So it’s two parts.-type
to tellfind
there will be a specific type to look for, and thef
flag, which means file. Meaning, it will only find filesThe output of find is not sorted alaphabetically, so before piping the output to
tail
, we first pipe it tosort
, which by default will sort alphanumerically, which we then pipe totail
to grab just the last two files, and finally we get to thexargs
bit.Here I added the
-n 1
argument toxargs
to get it to work on the files one at a time. This isn’t actually necessary. You could just run it asxargs rm
. I didn’t realize that before I posted the command. (I’m still learning too! The learning never ends. :D )Thanks so much harsh!!! I will study this and hit Enter after I understand it.
Thanks again, that’s epic.
You’re welcome! Happy I could help.
One other quick note, do the filenames or directories have spaces in them? If they do, that will cause a problem with the command as it is and need some additional modification. I accounted for the possible spaces in the directory names with the find command, but not with
xargs
. I just realized that as I was looking it over again.deleted by creator