• meteokr@community.adiquaints.moe
      link
      fedilink
      arrow-up
      1
      arrow-down
      6
      ·
      6 months ago

      Oh thanks for the tip! I’ve edited my comment to reflect the minimum of 4 drives for a RAID6 array.

      I’ve not used RAID6 for a small array like that before so I didn’t know it had a conventional lower limit. From the technical sense it doesn’t have to have 4 drives, it just wouldn’t make any sense to use it that way so I see why software wouldn’t support such a use case.

      • emptiestplace
        link
        fedilink
        arrow-up
        4
        ·
        6 months ago

        From the technical sense it doesn’t have to have 4 drives

        Please explain how you think you can distribute two sets of parity data across a three drive array?

        • meteokr@community.adiquaints.moe
          link
          fedilink
          arrow-up
          1
          arrow-down
          1
          ·
          edit-2
          6 months ago

          Drive 1: A, Drive 2: 1/2 A, Drive 3: 2/2 A. Drive 2 + Drive 3 = Drive 1. Hmm that would only be one set of the party though. So you could also add 1/2 of A to Drive 1, and 2/2 to Drive 2 so that the parity on Drive 1 + Drive 2 = Drive 3. Which is extremely silly, and doesn’t make a lot of sense to use in the real world.