• @ster
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    23 years ago

    If you draw a graph it’s nice to get some intuition for why: the area under the inverse is the area to the left of the curve up to a given point. This is equal to the area of the “rectangle” minus the are under the original curve :D

    • @ster
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      23 years ago

      Interesting to find another vegan mathematician on Lemmy!

    • @k_o_tOP
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      13 years ago

      it’s beautiful how such a random thing could have such a simple, yet hard to stumble upon explanation…

  • @Eli
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    2
    edit-2
    3 years ago

    deleted by creator

    • @k_o_tOP
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      24 years ago

      glad this is helpful for someone :)

      btw, I just spotted a little error in integration of arctan(x), it’s supposed to be x*arctan(x)-tan'(cos(arctan(x))) instead of x*arctan(x)+tan'(cos(arctan(x))), fixed now

      • @Eli
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        edit-2
        3 years ago

        deleted by creator

  • @ErisGuidesMe
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    13 years ago

    I think the derivation you wrote is wrong but the outcome is correct. Looks like a typo. Wouldn’t the integration by parts step give us u\mu(u) - \int \mu(u)du ?

    Also I believe that this is possibly the building blocks of the Laplace Transform. It looks really similar at least.

    • @k_o_tOP
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      13 years ago

      oops, yeah, that’s a typo, thanks for pointing out, i fixed it now